fixed some index entries
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@@ -6,8 +6,9 @@
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A common problem in statistics is to estimate from a probability
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distribution one or more parameters $\theta$ that best describe the
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data $x_1, x_2, \ldots x_n$. \enterm{Maximum likelihood estimators}
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(\enterm[mle|see{Maximum likelihood estimators}]{mle},
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data $x_1, x_2, \ldots x_n$. \enterm[maximum likelihood
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estimator]{Maximum likelihood estimators} (\enterm[mle|see{maximum
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likelihood estimator}]{mle},
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\determ{Maximum-Likelihood-Sch\"atzer}) choose the parameters such
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that they maximize the likelihood of the data $x_1, x_2, \ldots x_n$
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to originate from the distribution.
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@@ -228,7 +229,7 @@ maximized respectively.
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\begin{figure}[t]
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\includegraphics[width=1\textwidth]{mlepropline}
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\titlecaption{\label{mleproplinefig} Maximum likelihood estimation
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of the slope of line through the origin.}{The data (blue and
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of the slope of a line through the origin.}{The data (blue and
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left histogram) originate from a straight line $y=mx$ trough the origin
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(red). The maximum-likelihood estimation of the slope $m$ of the
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regression line (orange), \eqnref{mleslope}, is close to the true
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@@ -257,6 +258,7 @@ respect to $\theta$ and equate it to zero:
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This is an analytical expression for the estimation of the slope
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$\theta$ of the regression line (\figref{mleproplinefig}).
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\subsection{Linear and non-linear fits}
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A gradient descent, as we have done in the previous chapter, is not
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necessary for fitting the slope of a straight line, because the slope
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can be directly computed via \eqnref{mleslope}. More generally, this
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@@ -275,6 +277,7 @@ exponential decay
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Such cases require numerical solutions for the optimization of the
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cost function, e.g. the gradient descent \matlabfun{lsqcurvefit()}.
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\subsection{Relation between slope and correlation coefficient}
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Let us have a closer look on \eqnref{mleslope}. If the standard
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deviation of the data $\sigma_i$ is the same for each data point,
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i.e. $\sigma_i = \sigma_j \; \forall \; i, j$, the standard deviation drops
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