diff --git a/programming/exercises/control_flow.tex b/programming/exercises/control_flow.tex
index 84d48da..99984f2 100644
--- a/programming/exercises/control_flow.tex
+++ b/programming/exercises/control_flow.tex
@@ -14,7 +14,7 @@
 %%%%% text size %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
 \usepackage[left=20mm,right=20mm,top=25mm,bottom=25mm]{geometry}
 \pagestyle{headandfoot}
-\header{{\bfseries\large Exercise 5}}{{\bfseries\large Control Flow}}{{\bfseries\large 30. October, 2018}}
+\header{{\bfseries\large Exercise 5}}{{\bfseries\large Control Flow}}{{\bfseries\large 05. November, 2019}}
 \firstpagefooter{Dr. Jan Grewe}{Phone: 29 74588}{Email:
   jan.grewe@uni-tuebingen.de}
 \runningfooter{}{\thepage}{}
@@ -47,11 +47,9 @@ following pattern: ``variables\_datatypes\_\{lastname\}.m''
 \begin{questions}
   \question Implement \code{for} loops in which the  \emph{running variable}:
   \begin{parts}
-    \part ... assumes values from 0 to 10. Print the value of the running variable for each iteration step.
+    \part ... assumes values from 0 to 10. Print (\code{disp}) the value of the running variable for each iteration step.
     \begin{solution}
-      for i = 1:10
-      disp(i);
-      end;
+      for i = 1:10 disp(i); end;
     \end{solution}
     \part ... assumes values from 10 to 0. Print out the value for each iteration.
     \part ... assumes values from 0 to 1 in steps of 0.1. Print out the value for each iteration.
@@ -59,12 +57,12 @@ following pattern: ``variables\_datatypes\_\{lastname\}.m''
 
   \question Indexing in vectors:
   \begin{parts}
-    \part Define a vector \code{x} that contains values ranging from 101 to 200.
+    \part Define a vector \code{x} that contains values ranging from 101 to 200 in steps of 1.
     \part Use a \code{for} loop to print each element of \code{x}. Use the running variable for the indexing.
     \begin{solution}
       \code{for i = 1:length(x); disp(x(i)); end}
     \end{solution}
-    \part Do the same without use the running variable directly (not for indexing).
+    \part Do the same without using the running variable directly (not for indexing).
     \begin{solution}
       \code{for i : x; disp(i); end;}
     \end{solution}
@@ -74,7 +72,7 @@ following pattern: ``variables\_datatypes\_\{lastname\}.m''
   \begin{parts}
     \part Use a loop to calculate the arithmetic mean. The mean is defined as:
     $\overline{x}=\frac{1}{n}\sum\limits_{i=0}^{n}x_i $.
-    \part Use a loop to estimate the stadard deviation:
+    \part Use a loop to estimate the standard deviation:
     $\sigma=\sqrt{\frac{1}{n}\sum\limits_{i=0}^{n}(x_i-\overline{x})^2}$).
     \part Search the MATLAB help for functions that do the calculations for you :-).
   \end{parts}
@@ -85,13 +83,13 @@ following pattern: ``variables\_datatypes\_\{lastname\}.m''
     \part ... iterates endlessly. You can interrupt the execution with the command \code{Strg + C}.
   \end{parts}
 
-  \question Use an endless \code{while} loop to individually print out the elements of a vector that contains 10 elements. Stop the execution after all elements have been printed.
+  \question Use an endless \code{while} loop to individually display the elements of a vector that contains 10 elements. Stop the execution after all elements have been displayed on the command line.
 
   \question Use the endless \verb+while+ loop to draw random numbers
   (\verb+randn+) until you hit one that is larger than 1.33.
   \begin{parts}
     \part Count the number of required iterations.
-    \part Use a \code{for} loop to run the previous test 1000 times. Remember all counts and calculate the mean of it.
+    \part Use a \code{for} loop to run the previous test 1000 times. Store all counts and calculate the mean of it.
     \part Create a plot that shows for each of the 1000 trials, how often you had to draw.
     \part Play around with the threshold. What happens?
   \end{parts}